Find the Speed of a Swinging Rock with a 10 ft Radius | Physics Help

Thread starter tman
Start date Oct 18, 2004
Tags

Physics

AI Thread Summary

To find the speed of a rock swinging in a circle with a radius of 10 feet and a centripetal acceleration of 16.9 ft/sec², the formula v = √(a * r) can be used, where v is speed, a is centripetal acceleration, and r is radius. Plugging in the values, the calculation yields a speed of approximately 13 ft/sec. The user confirmed that they completed the problem and arrived at the same speed. This demonstrates the application of centripetal motion principles in physics. The discussion effectively illustrates a practical example of calculating speed from centripetal acceleration.

Oct 18, 2004

tman

A rock tied to a string is swung around in a circle with a radius of 10 ft. The centripetal acceleration is 16.9 ft/sec2.
Calculate the speed of the rock.

_____________ft/sec.

Physics news on Phys.org

Oct 18, 2004

Tide

Science Advisor

Homework Helper

What exactly have you done or tried so far?

Oct 18, 2004

tman

i finished the problem and i got 13 i thanks though

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »

Thread 'Understanding Forces and their Vector Components'

I was told forces are vectors so they can be divided into x and y components, but what about the normal force or the force of static friction? do you divide those into x and y components if say you had a block that was lying on an angled surface?

View full post »