Find the trajectory of a boat that moves in a river

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SUMMARY

The trajectory of a boat moving across a river is defined by the equation r = Dsecθ/(secθ + tanθ)VB/VR, where D is the river width, VR is the river's flow velocity, and VB is the boat's velocity directed towards point Q. The discussion emphasizes the importance of treating the boat's position and velocity as vectors to accurately determine its path. The boat's velocity relative to the shore must also be considered, as it affects the trajectory calculation.

PREREQUISITES
  • Understanding of vector mathematics
  • Knowledge of trigonometric functions (secant and tangent)
  • Familiarity with the concepts of relative velocity
  • Basic principles of physics related to motion in fluids
NEXT STEPS
  • Study vector addition and subtraction in physics
  • Learn about relative velocity in moving fluids
  • Explore trigonometric identities and their applications in physics
  • Investigate the effects of current on boat navigation
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and fluid dynamics, as well as anyone involved in navigation or maritime engineering.

david22
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Homework Statement


A boat part from the point P of the bank of a river, with width D, and that flows with a constant velocity VR, and moves with a constant velocity VB, directed towars a point Q, located on the other side of the river directly in front of P. If r is the instantaneous distance of the boat respect to Q and θ is the instantaneous angle between r and PQ, show that the trajectory of the boat is determined by:

r=Dsecθ/(secθ+tanθ)VB/VR

Homework Equations


The Attempt at a Solution


I am completely lost in this problem; I to put the instantaneous distance of the boat r as a vector and a took Q as my origin r = cos(90-θ)i+sen(90-θ)j but then i don't know what else to do; I would appreciate your help a lot
 
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david22 said:

Homework Statement


A boat part from the point P of the bank of a river, with width D, and that flows with a constant velocity VR, and moves with a constant velocity VB, directed towars a point Q, located on the other side of the river directly in front of P. If r is the instantaneous distance of the boat respect to Q and θ is the instantaneous angle between r and PQ, show that the trajectory of the boat is determined by:

r=Dsecθ/(secθ+tanθ)VB/VR

Homework Equations





The Attempt at a Solution


I am completely lost in this problem; I to put the instantaneous distance of the boat r as a vector and a took Q as my origin r = cos(90-θ)i+sen(90-θ)j but then i don't know what else to do; I would appreciate your help a lot

Have you copied the problem text correctly? "A boat part from the point P of the bank of a river, with width D, and that flows with a constant velocity VR, and moves with a constant velocity VB, directed towars a point Q, located on the other side of the river directly in front of P." If the boat moves with constant velocity it never reaches point Q. Was not it constant speed with respect to the river?

You are right, treat the position and velocity of the boat as vectors. The velocity of the boat with respect to the river points towards Q. What is the velocity of the boat with respect to the shore?

ehild
 

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