Find the velocity as it reaches the water

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To find the velocity of the stones as they reach the water, kinematic equations should be used, focusing on initial velocity, final velocity, distance, and acceleration due to gravity. For the stone thrown downward, the final velocity can be calculated using the formula that incorporates initial velocity and distance. The pebble thrown upward will return to the same speed it was thrown with, but in the opposite direction upon descent. Average velocity for both stones can be determined through the formula for uniformly accelerated motion. The negative sign in the average velocity indicates the downward direction of motion.
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Q. A boy stands at the edge of a bridge 20.0 m above a river
and throws a stone straight down with a speed of 12.0 m/s.
He throws another pebble straight upward with the same
speed so that it misses the edge of the bridge on the way
back down and falls into the river. For each stone find (a)
the velocity as it reaches the water and (b) the average
velocity while it is in flight.

Note: Ignore the affects of air resistance.

Can't figure it out, please help this is due monday
 
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First, please show us what you have done.
 
SORRY , yeah i shud have written that i attempted it, can't figure out which formula to use , does it mean the initial velocity for both pebbles is 20 m/s and the distance is 20m
 
a) Some hints: for the pebble thrown straight down, try to find a kinematic formula that relates initial velocity, final velocity, distance, and acceleration. For the stone thrown up, remember that when you throw something up vertically, assuming no air resistance, it returns to the ground with the same speed it was released with.
b) This is uniformily accelerated motion: what formula is used for v_{av}?
 
okay thanks, i can't find a formula so do i take more than one equation to solve for unknowns? i dun get it
 
for part b the asnwer id -12 m/s right negative because of the direction?
 
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