Physicsisfun2005
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I don't have the answers in the back of my book and I really want to know if i did this correctly since its graded. the Problem is: Let the region bounded by x^2+y^2=9 be the base of a solid. Find the Volume if cross sections taken perpendicular to the base are isosceles right triangles.
i know a triangle is .5bh and the base of it will be \sqrt{9-x^2} so for volume the final answer is \pi\int 4.5-.5x^2 dx with the limits from -3 to 3 and i get 18\pi for volume.....is this right?
i know a triangle is .5bh and the base of it will be \sqrt{9-x^2} so for volume the final answer is \pi\int 4.5-.5x^2 dx with the limits from -3 to 3 and i get 18\pi for volume.....is this right?
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