Gundown64
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Homework Statement
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
y = 5x, y = 5\sqrt{x} about y = 5
Homework Equations
A(x)=∏(R2-r2)
The Attempt at a Solution
A(x)=∏(5x)2-(5\sqrt{x})2)
A(x)=∏(25 x2 - \frac{10}{3}x\frac{3}{2})
V=∏\int^{1}_{0}(25x2- \frac{10}{3}x\frac{3}{2})dx
V=∏(\frac{25}{3}x3-\frac{4}{3}x\frac{5}{2}) {0,1}
V=∏(\frac{25}{3}-\frac{4}{3})
V= \frac{21}{3}∏
Where did I go wrong? I can't figure out the about y=5. If I am correct, you would usually subtract 5 from the two radii, but since they intersect at y=5, the just flip on that intersection point and thus we don't need to find the lost area. Bad explanation, I know, maybe someone can explain it to me.
Thanks in advance!