Coyote falling down with a parachute holding an anvil at 10m/s. At 50m he drops the anvil.
A) How long does it take for the anvil to hit the ground?
B) what is the velocity of the anvil right before it hits the ground?
X= Xo + V0T+1/2A(T^2)
g= 9.8 m/s^2
The Attempt at a Solution
50m = 10m/sT + 4.9m/s^2T^2
i use the quadratic equation and got t= 1.14 and -2.143
however i know this is wrong since i can not get a negative second and it seen like the "s" cancel out and you got T = a number without second.
also i know the answer is 2.33 s for (A) but want to know how to get that answer.