Find Time t_0 for a Beam to Not Catch Up with Earth

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Homework Statement


You start at t=0 at rest on Earth and accelerate with uniform acceleration a away form earth.
Find a point in time t_0 such that when a beam emitted from Earth at t>t_0won't catch up.


Homework Equations


x(t)=c^2/a(\sqrt{1+\frac{a^2}{c^2}t^2}-1)


The Attempt at a Solution


I think that light travel with velocity c. So if the beam is emitted at t=t_1 then at time t, the beam have traveled c(t-t_1). So I try to find the solution for x(t)=c(t-t_1), and I end up with the following expression for t:
t=\frac{a}{2c}\frac{t_1(2-a/c t_1)}{(a/c - a^2/c^2 t_1)}

According to this the time would be negatic in the intervall t_1=c/a and t_1=2c/a So I think in this intevall the beam won't be able to catch up, but after t_1=2c/a the time becomes positive again, which I don't know how to interpret.
Am I approaching this problem the wrong way?
 
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Think about it this way: will you ever accelerate to a speed greater than that of light? If not, how can you possibly outrun light?
 
Well it is problem 3.9 in D'inverno Introducing Einsteins relativity. I agree that it seem impossible but the problem statement is that if you get a large enough headstart the light won't catch up.
 
What assumptions are you supposed to make?
 
negatic?
 
You should be able to show that your world line is a hyperbola. Find its asymptotes.
 
zardiac said:
t=\frac{a}{2c}\frac{t_1(2-a/c t_1)}{(a/c - a^2/c^2 t_1)}

Note t approaches ∞ as the denominator on the right approaches 0.
 
Let's say you keep uniform acceleration a, relative to the stationary observer. After c/a time you will be moving at the speed of light. To keep uniform acceleration you need infinite amount of energy. I think the answer is c/a, just the problem is that you can't keep uniform acceleration.
 
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Myslius said:
Let's say you keep uniform acceleration a, relative to the stationary observer. After c/a time you will be moving at the speed of light. To keep uniform acceleration you need infinite amount of energy. I think the answer is c/a, just the problem is that you can't keep uniform acceleration.
You've misinterpreted the problem. The acceleration is uniform relative to the moving observer. As you noted, you can't have a uniform acceleration relative to the stationary observer indefinitely.
 
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