Find Unknown Weight w/ Ideal Spring Problem

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An ideal spring problem involves a scale reading different weights, where a 100N weight shows 40 and a 200N weight shows 60. The user initially struggles to find a consistent spring constant (k), calculating different values for each weight. A hint reveals the need to account for an unknown constant weight affecting the scale's readings. By solving the equation (100+c)/40=(200+c)/60, the user determines the constant weight (c) to be 100, leading to a correct scale reading of 50. This approach effectively resolves the issue and confirms the solution's validity.
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Homework Statement


An ideal spring hangs next to a scale, when a 100N weight the scale reads 40, when a 200N weight is attached it reads 60. Using an unknown weight reads 30.

Homework Equations


F=-kx

The Attempt at a Solution


I attempted to find the value of k for the spring however when calculating k for the 100N it is 2.5N/m and for the 200N it is 3.3N/m which doesn't make sense to me since I would've thought k would be constant. I also tried using F/x=F/x but this also didn't work so I'm completely lost.
 
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Potatochip911 said:

Homework Statement


An ideal spring hangs next to a scale, when a 100N weight the scale reads 40, when a 200N weight is attached it reads 60. Using an unknown weight reads 30.

Homework Equations


F=-kx

The Attempt at a Solution


I attempted to find the value of k for the spring however when calculating k for the 100N it is 2.5N/m and for the 200N it is 3.3N/m which doesn't make sense to me since I would've thought k would be constant. I also tried using F/x=F/x but this also didn't work so I'm completely lost.
Hint: you are not told what the scale reads when no weight is attached.
 
haruspex said:
Hint: you are not told what the scale reads when no weight is attached.
Thanks! I solved for the constant weight that is being applied to the scale.
(100+c)/40=(200+c)/60
This gave c=100
Including this constant weight in the equations gave the correct scale reading of 50.
I'm assuming this is how you would solve it because it produced the correct answer although there might be a different way.
 
Potatochip911 said:
Thanks! I solved for the constant weight that is being applied to the scale.
(100+c)/40=(200+c)/60
This gave c=100
Including this constant weight in the equations gave the correct scale reading of 50.
I'm assuming this is how you would solve it because it produced the correct answer although there might be a different way.
That's as good a way as any.
 
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