Find v_o and i_o in the circuit

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SUMMARY

The discussion focuses on solving for the output current (i_o) and input current (i_x) in a circuit using Kirchhoff's Current Law (KCL). The user initially calculated i_o as 7.2 A but found a discrepancy with the book's answer of 6 A. The correct approach involves applying KCL at node 'a' and recognizing that all components are in parallel, leading to the equation 6A - i_o - (i_o/4) - i_x = 0, which accurately represents the current distribution in the circuit.

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The 6 A is 9 A for the problem I'm solving for.

Homework Equations


Only using KCL

The Attempt at a Solution



I tried using KCL @ node a:

9 = io + i0/4

I get io = 7.2 A.

The answer in the book is 6A. What am I doing wrong?
 
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What about the current through the 8 Ω resistor?
 
You should get something like:

##6A - i_o - \frac{i_o}{4} - i_x = 0##

Then using the fact everything is in parallel, you should be able to find what you need.
 

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