Find Values of a and b for Perpendicular Vectors

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noahsdev
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Homework Statement



If [itex]\underline{v}[/itex] = a[itex]\underline{i}[/itex] + 2[itex]\underline{j}[/itex] + 3[itex]\underline{k}[/itex] and [itex]\underline{w}[/itex] = 2[itex]\underline{i}[/itex] +b[itex]\underline{j}[/itex] - [itex]\underline{k}[/itex] and |[itex]\underline{v}[/itex]| = |[itex]\underline{w}[/itex]|, find the values of a and b so that [itex]\underline{v}[/itex] and [itex]\underline{w}[/itex] are perpendicular.

If v = ai+3j+3k and w = 2i+bj-k and |v| = |w|, find the values of a and b so that v and w are perpendicular.

Homework Equations



[itex]\underline{a}[/itex] - ([itex]\underline{a}[/itex].[itex]\underline{\hat{b}}[/itex])[itex]\underline{\hat{b}}[/itex]

The Attempt at a Solution


sqrt(a2+13) = sqrt(b2+5)

I am so confused right now. Any help would be great. Thanks
 
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noahsdev said:

Homework Statement



If [itex]\underline{v}[/itex] = a[itex]\underline{i}[/itex] + 2[itex]\underline{j}[/itex] + 3[itex]\underline{k}[/itex] and [itex]\underline{w}[/itex] = 2[itex]\underline{i}[/itex] +b[itex]\underline{j}[/itex] - [itex]\underline{k}[/itex] and |[itex]\underline{v}[/itex]| = |[itex]\underline{w}[/itex]|, find the values of a and b so that [itex]\underline{v}[/itex] and [itex]\underline{w}[/itex] are perpendicular.


Homework Equations



[itex]\underline{a}[/itex] - ([itex]\underline{a}[/itex].[itex]\underline{\hat{b}}[/itex])[itex]\underline{\hat{b}}[/itex]

The Attempt at a Solution


sqrt(a2+13) = sqrt(b2+5)

I am so confused right now. Any help would be great. Thanks

That's one equation. To get another equation, use the requirement that u and v be perpendicular. Hint: There is a simple operation that can be used to determine whether two vectors are perpendicular.
 
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Mark44 said:
That's one equation. To get another equation, use the requirement that u and v be perpendicular. Hint: There is a simple operation that can be used to determine whether two vectors are perpendicular.

Thanks, haha, so simple. I'm so angry at myself now. :)