For what values of a are y=a^x and y=1+x tangent at x=0? Explain
The Attempt at a Solution
Since both equations are tangent at x=0 i set their derivatives equal to each other in hopes of getting a a^xln(a)=1 I then substitute x in that equation with 0 and end up with ln(a)=1.
I end up with a = e. Is this correct?