Find Velocity: Homework Equations & Solutions

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SUMMARY

The discussion focuses on solving a physics problem involving the calculation of velocity using the equations for potential energy (PE = MGH) and kinetic energy (KE = 1/2 x m x v^2). Participants clarify that the formula V = d/t is only applicable under constant velocity conditions, emphasizing the importance of accounting for acceleration in projectile motion. The correct velocity is determined to be approximately 20.98 m/s, derived from the kinetic energy formula. This highlights the necessity of understanding the distinction between speed and velocity in physics problems.

PREREQUISITES
  • Understanding of potential energy (PE) and kinetic energy (KE) equations
  • Knowledge of the relationship between distance, time, and velocity
  • Familiarity with concepts of acceleration in projectile motion
  • Ability to manipulate algebraic equations to solve for unknown variables
NEXT STEPS
  • Study the derivation and application of the kinetic energy formula (KE = 1/2mv^2)
  • Learn about projectile motion and the effects of acceleration on velocity
  • Explore the differences between speed and velocity in physics
  • Practice solving physics problems involving energy conservation principles
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Students studying physics, educators teaching mechanics, and anyone seeking to improve their problem-solving skills in energy-related physics topics.

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Homework Statement


screenshot of problem: imgday.net/?di=8RMN

Homework Equations


PE = MGH
KE = 1/2 x m x v^2
V = d/t

The Attempt at a Solution


I know how to find the PE & KE, but I stumped at finding the velocity and it keeps saying I get the wrong answer or would it just be 20 m/s?
 
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rqureshi24 said:

Homework Statement


screenshot of problem: imgday.net/?di=8RMN

Homework Equations


PE = MGH
KE = 1/2 x m x v^2
The above formulas are very important to solving this problem.
V = d/t
Be careful with that one. v = d/t only applies for constant velocity (i.e. if a = 0). But acceleration is involved with this problem. The projectile is certainly not moving at a constant velocity.

The Attempt at a Solution


I know how to find the PE & KE, but I stumped at finding the velocity and it keeps saying I get the wrong answer or would it just be 20 m/s?

The answer may just be 20 m/s, but you should be able to explain why that is.

If you've already found KE, then use your KE = ½mv2 formula. Solve for v. :wink:
 
Be careful with that one. v = d/t only applies for constant velocity (i.e. if a = 0). But acceleration is involved with this problem. The projectile is certainly not moving at a constant velocity.
Oh, thank you so much for the tidbit. My physics teacher never explained to us like that. It's true that you learn something new everyday. :)

The answer may just be 20 m/s, but you should be able to explain why that is.
It's not 20 m/s, it's 20.976 and rounded to 20.98, isn't it because speed & velocity are the same thing?

If you've already found KE, then use your KE = ½mv2 formula. Solve for v. :wink:
I wish I thought of that earlier, now I got the correct answer using that formula! I feel so dumb for wasting so much time trying to figure it out.
 

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