Find Velocity: Homework Equations & Solutions

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The discussion focuses on solving a physics problem involving potential energy (PE), kinetic energy (KE), and velocity. Participants clarify that the formula V = d/t only applies under constant velocity conditions, which is not the case here due to acceleration. The correct approach involves using the kinetic energy formula KE = ½mv² to find the velocity. One participant expresses relief after realizing this method leads to the correct answer, emphasizing the importance of understanding the concepts behind the formulas. The conversation highlights the learning process in physics and the value of clear explanations.
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Homework Statement


screenshot of problem: imgday.net/?di=8RMN

Homework Equations


PE = MGH
KE = 1/2 x m x v^2
V = d/t

The Attempt at a Solution


I know how to find the PE & KE, but I stumped at finding the velocity and it keeps saying I get the wrong answer or would it just be 20 m/s?
 
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rqureshi24 said:

Homework Statement


screenshot of problem: imgday.net/?di=8RMN

Homework Equations


PE = MGH
KE = 1/2 x m x v^2
The above formulas are very important to solving this problem.
V = d/t
Be careful with that one. v = d/t only applies for constant velocity (i.e. if a = 0). But acceleration is involved with this problem. The projectile is certainly not moving at a constant velocity.

The Attempt at a Solution


I know how to find the PE & KE, but I stumped at finding the velocity and it keeps saying I get the wrong answer or would it just be 20 m/s?

The answer may just be 20 m/s, but you should be able to explain why that is.

If you've already found KE, then use your KE = ½mv2 formula. Solve for v. :wink:
 
Be careful with that one. v = d/t only applies for constant velocity (i.e. if a = 0). But acceleration is involved with this problem. The projectile is certainly not moving at a constant velocity.
Oh, thank you so much for the tidbit. My physics teacher never explained to us like that. It's true that you learn something new everyday. :)

The answer may just be 20 m/s, but you should be able to explain why that is.
It's not 20 m/s, it's 20.976 and rounded to 20.98, isn't it because speed & velocity are teh same thing?

If you've already found KE, then use your KE = ½mv2 formula. Solve for v. :wink:
I wish I thought of that earlier, now I got the correct answer using that formula! I feel so dumb for wasting so much time trying to figure it out.
 
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