Find Volume of 30.0 acre-ft Water in SI Units

  • Thread starter Thread starter r-soy
  • Start date Start date
  • Tags Tags
    Water
AI Thread Summary
To find the volume of 30.0 acre-ft of water in SI units, first recognize that one acre-foot equals 43,560 cubic feet. To convert acre-feet to cubic meters, use the conversion factor where 1 cubic foot equals 0.0283168 cubic meters. Therefore, 30.0 acre-ft translates to approximately 30.0 * 43,560 * 0.0283168 cubic meters. The final volume in SI units is about 1,134.0 cubic meters. This calculation provides a clear understanding of the water volume in a reservoir.
r-soy
Messages
170
Reaction score
1
The amount of water in reservoirs is often measured in acre-ft. One acre-ft is a volume that covers an area of one acre to a depth of one foot. An acre is 43,560 ft2. Find the volume in SI units of a reservoir containing 30.0 acre-ft of water.


I want the idea to solve this question

then I try to solve it
 
Physics news on Phys.org
hi r-soy! :wink:

the SI unit of volume is m3, so you'll need to use the conversion factor from ft to m …

what do you get? :smile:
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top