Find Wavelength of 8cm Closed Pipe: 7th Harmonic

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The discussion focuses on calculating the wavelength of an 8cm closed pipe at its 7th harmonic. The initial calculation mistakenly found the length instead of the wavelength, leading to confusion. The correct formula for wavelength is λ = 4L/n, which results in λ = 0.045m for the given parameters. Clarification was provided that this calculation is valid for a pipe closed at one end. The final consensus confirms that the calculated wavelength is accurate for the specified conditions.
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Homework Statement


What is the wavelength of an 8cm closed pipe when it is sounding the 7th harmonic?

Homework Equations


L=λn/4

The Attempt at a Solution


L=(.08m*7)/(4)
L=0.14m
Am I correct?
 
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ThePhysicsXV said:
L=(.08m*7)/(4)
L=0.14m
Am I correct?

check your calculation-are you finding out the pipe length or wavelength?
 
drvrm said:
check your calculation-are you finding out the pipe length or wavelength?
Wavelength
 
drvrm said:
check your calculation-are you finding out the pipe length or wavelength?
Oh yeah wavelength, so is
λ=4L/n
λ=4(.08)/7
Since is 7th harmonic.
λ= .045m
 
ThePhysicsXV said:
Oh yeah wavelength, so is
λ=4L/n
λ=4(.08)/7
Since is 7th harmonic.
λ= .045m
I think its correct!
 
Seems a bit small to me. Is the pipe closed on both ends ? Can you check your relevant equation? Where does it come from ? Do you understand it ? Can you make a drawing ?

[edit] I was mistaken. Your answer is right for a pipe that is closed on one end and open on the other.
 
Last edited:

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