Finding 1-forms on Plane Vectors using dx1 and x2

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Homework Statement



Given three vectors on a plane (x1,x2) with coefficients a and b:

v1 = a1*x1 + b1*x2
v2 = a2*x1 + b2*x2
v3 = a3*x1 + b2*x2 (presumably not used in this part)

Find the 1-forms (below) on the vectors.

Homework Equations



The given 1-forms are:
w1 = dx1
w2 = x2*dx1

The Attempt at a Solution



I can write w1=dx1 as,

dx1 = (dx1/dv1)*dv1 + (dx1/dv2)*dv2

This would seem to state dx1 in terms of a basis dv1, dv2. However, I still don't know x2. This is a problem from our last homework assignment that I didn't know how to do. I'm only posting it in this section because I'm sure we'll have more. Any help is appreciated.
 
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Ok, so I'm pretty sure I'm not supposed to put dx in terms of dv1 since I have three vectors and it's only a 2D plane. So what does it mean to calculate the 1-form "on" a vector? Each vector obviously has a component in x1 and x2.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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