- #1

lyarbrough

- 2

- 0

## Homework Statement

Hi, I'm trying to understand how you solve for the problem lim [(2+h)^5 -2^5]/h as h→0

I already have the solution, but I want to make sure my understanding of how it's done is correct.

## Homework Equations

I'm suppose to be using the definition of the derivative [f(x+h)-f(x)]/h

## The Attempt at a Solution

So what I have is that lim [(2+h)^5 -2^5]/h as h→0 is = f'(2). I'm assuming that's because 2 was substituted in for f(x) in the definition of a derivative.

The next step I have is that f(x)= ? and then f'(x) = x^5. I'm just wondering if it's just re substituting in x for the 2? I know how to solve it from there with the chain rule, I'm just wondering how they determine f'(x). Thanks!