Finding acceleartion components

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To find the acceleration components of a proton moving at 0.9c under a force F, the equation F = (ma)/(1 - (v^2/c^2))^3/2 is used, with the correct adjustment being the square root of (1 - v^2/c^2). After calculating the x and y components of acceleration, the next step involves determining the angle between the force vector and the acceleration vector. This can be done using the dot product of the two vectors. The discussion emphasizes ensuring the correct application of relativistic equations and vector analysis for accurate results. Understanding these concepts is crucial for solving problems in relativistic dynamics.
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So the problem goes:

A proton, with rest mass 1.67x10^-27 kg, is moving at v=.9c (where c= speed of light) in the positive x direction, relative to the reference frame of a physics laboratory. Then, a constant force F=(-3.00 X 10^-12)i + (5.00 X 10^-12)j is applied to proton

a) find x and y comps of accl of proton after F was just applied

Bassically, i just used this equation to solve for x and y comps of accl:

F= (ma)/(1-(v^2/c^2))^3/2 and solved for a, and plugged in x and y comps..

is that right?

b) find the angle between F and the accleration that was calculated in part a...

not sure how to go about that.. is the dot product of F and a taken in order to find the angle?

thanks!
 
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youve got the right idea for a)...except its the square root of (1-v^2/c^2)...so^1/2

and for b)..im supposing you have to find the force vector components..and then, you know
 
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