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## Homework Statement

[/B]

A belt moves over three pulleys at a constant speed v

_{0}[ft/s]. Knowing that the normal component of the acceleration of the portion of the belt in contact with pulley B is a

_{B,n}=90 [ft/s

^{2}]. Determine:

(a) speed of the belt, v

_{0}[ft/s], and

(b) normal component of the acceleration of the portion of the belt in contact with pulley A, a

_{A,n}[ft/s

^{2}].

Radii of pulleys are: r

_{A}=3 [in], r

_{B}=1 [in], r

_{C}=2.5 [in].

## Homework Equations

a

_{n}= ||

**v**x

**a**|| / ||

**v**||

## The Attempt at a Solution

[/B]

I believe the first step would be to find the acceleration of the belt given the normal component. Since the belt is moving at a constant speed, both the tangential component and the acceleration would be 0 ft/s

^{2}.

After that, we should put the numbers we have into the equation and get:

90 ft/s

^{2}= ||

**v**x 0 ft/s

^{2}|| / ||

**v**||

..and solve for velocity. However I'm unsure how to do this since none of the numbers I'm given are in component vector form.

For part B, I would assume it is just a

_{A,n}divided by 3 since the radius of A is 3 times larger than B?