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Homework Statement
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A belt moves over three pulleys at a constant speed v_{0} [ft/s]. Knowing that the normal component of the acceleration of the portion of the belt in contact with pulley B is a_{B,n}=90 [ft/s^{2} ]. Determine:
(a) speed of the belt, v_{0} [ft/s], and
(b) normal component of the acceleration of the portion of the belt in contact with pulley A, a_{A,n} [ft/s^{2} ].
Radii of pulleys are: r_{A} =3 [in], r_{B} =1 [in], r_{C}=2.5 [in].
Homework Equations
a_{n} = v x a / v
The Attempt at a Solution
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I believe the first step would be to find the acceleration of the belt given the normal component. Since the belt is moving at a constant speed, both the tangential component and the acceleration would be 0 ft/s^{2}.
After that, we should put the numbers we have into the equation and get:
90 ft/s^{2} = v x 0 ft/s^{2} / v
..and solve for velocity. However I'm unsure how to do this since none of the numbers I'm given are in component vector form.
For part B, I would assume it is just a_{A,n} divided by 3 since the radius of A is 3 times larger than B?
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