Finding all the values of the circuit

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Discussion Overview

The discussion revolves around determining the values of various labeled variables in a circuit, given that the output terminal voltage is measured at 3.367V. Participants explore the implications of this measurement on the input voltage and other circuit parameters.

Discussion Character

  • Homework-related
  • Debate/contested
  • Exploratory

Main Points Raised

  • One participant states that since the output voltage is 3.367V, the input voltage (V_in) is also 3.367V, but questions remain about the other variables.
  • Another participant suggests that if the output voltage cannot be lower than the voltage source, there must be no voltage drop between the two locations, implying a specific condition for the circuit.
  • A different participant considers solving the problem in reverse but indicates that this approach does not yield a solution.
  • One participant requests additional details or a photo of the question associated with the circuit diagram to clarify the context.

Areas of Agreement / Disagreement

Participants express uncertainty about the nature of the question, with some suggesting it may be a trick question, while others feel more information is needed to proceed. No consensus is reached regarding the approach to solving the problem.

Contextual Notes

There are limitations in the provided information, as participants note the need for more details about the circuit and the associated question to accurately determine the values of the variables.

sis007
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Question: the output terminal voltage for the circuit shown is measured to be 3.367V. Determine the value of each of the labeled variables.

So V_in is also 3.367V .. but what about everything else...
 

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Hi sis007! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Is this a trick question? Because, for the output voltage to be no lower than the voltage source, there can be no voltage drop between the two locations.
 
Last edited by a moderator:
Then should I try solving it backward... It still doesn't work.
 
If you rule out the possibility of it being a trick question, then it seems there is more detail than you have provided here. Can you post a photo of the question that is associated with this diagram.
 

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