Finding angular acceleration of 2 masses on a rod

AI Thread Summary
To find the angular acceleration of a uniform rigid rod with attached masses, start by analyzing the forces acting on the system using a free-body diagram. The moment of inertia for the rod can be calculated using the formula I = 1/12ML^2, where M is the total mass. The gravitational forces acting on the point masses at the ends of the rod contribute to the torque about the pivot point. By applying Newton's second law for rotation, the angular acceleration can be determined from the net torque divided by the moment of inertia. This approach provides a structured method to solve for the angular acceleration when the rod is at a specified angle.
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Homework Statement



A uniform rigid rod with mass Mr = 5.9 kg, length L = 2.9 m rotates in the vertical xy plane about a frictionless pivot through its center. Two point-like particles m1 and m2, with masses m1 = 5.7 kg and m2 = 1.8 kg, are attached at the ends of the rod. What is the magnitude of the angular acceleration of the system when the rod makes an angle of 42.7° with the horizontal?

Homework Equations



all i know is that I= 1/12ML^2

The Attempt at a Solution



I honestly don't know where to star, could anyone guide me towards the right way
 
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Start by drawing a free-body diagram and identifying the forces on the rod.
 

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