Finding Angular speed and momentum

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SUMMARY

The discussion focuses on calculating the angular speed and momentum of a merry-go-round with a radius of 1.40m and a mass of 125kg, with a 60.0kg student standing on its edge. The initial angular speed is determined using the formula for angular momentum, L = Iω, where I represents the moment of inertia. The key takeaway is that the angular speed of the merry-go-round is identical to that of the student, and as the student moves inward, the moment of inertia changes, affecting the overall angular momentum.

PREREQUISITES
  • Understanding of angular momentum (L = Iω)
  • Knowledge of moment of inertia for solid disks
  • Familiarity with angular speed calculations
  • Basic principles of rotational dynamics
NEXT STEPS
  • Study the moment of inertia for various shapes, focusing on solid disks
  • Learn how to derive angular speed from angular momentum
  • Explore the conservation of angular momentum in closed systems
  • Practice problems involving rotating systems and variable mass distributions
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Students studying physics, particularly those focusing on rotational dynamics, as well as educators looking for practical examples of angular momentum and speed calculations.

artsim2011
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Homework Statement


The problem:
A merry-go-round has a radius of 1.40m and a mass of 125kg. You may consider the merry-go-round to be a solid disk. A 60.0kg student stands on the outer edge of the merry-go-round, 1.40m from the center(the axis of rotation). It takes 3.00s for the merry-go-round and the student to make one revolution. The student then walks radially inward to a point 0.350m from the axis of rotation and stands at that point.
Find:
a. What is the initial angular speed of the merry-go-round, expressed in rad/s?
b. What is the angular momentum of the student and merry-go-round?
c. What is the final angular speed of the merry-go-round?

Homework Equations


L = I\omega^2
L(initial) = L(final)

The Attempt at a Solution


After I used the information given I have the final and initial angular speed of the merry-go-round and the student combined. I don't know what equation I have to use to get the angular speed of just the merry go round. Finally I'm not sure how to go about using the data to get the angular momentum. The I variable has three different ones the initial and final of the student and the merry-go-round itself and the same thing goes for the angular speed do I just add the two angular speeds that I already have or is there something else I have to do. If I'm not asking specific enough questions or if I need to post more information then please let me know and thanks for any responses.
 
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artsim2011 said:
After I used the information given I have the final and initial angular speed of the merry-go-round and the student combined. I don't know what equation I have to use to get the angular speed of just the merry go round.
It is not clear what you mean by this. The angular speed of the merry-go-round is the same as the angular speed of the student at all times. Angular momentum is given by Iω where I = Imerry-go-round + Istudent. As the student moves, Istudent changes but Imerry-go-round does not.

Does this help?
 
Oh my god yes that helps I didn't understand they were the same I thought that they were different thank you so much.
 

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