Finding charge of a uniformly charged disk

AI Thread Summary
To find the total charge on a uniformly charged disk, the electric field and potential equations are provided, with known values at two distances from the center of the disk. The challenge lies in solving for the two unknowns: the radius (R) and surface charge density (σ). Substituting the known electric field (E) and potential (V) values into the equations allows for the elimination of variables by dividing the equations. This approach simplifies the problem, but users are seeking a more straightforward method to avoid losing points on a homework assignment. Ultimately, understanding the relationships between the variables is key to solving for the total charge on the disk.
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Along the axis of a uniformly charged disk, at a point 0.6 m from the center of the disk, the potential is 91.4 V and the magnitude of the electric field is 86.5 V/m; at a distance of 1.5 m, the potential is 46.8 V and the magnitude of the electric field is 27.0 V/m. Find the total charge residing on the disk.

I have both equation to finding the electric field and potential field for a uniform disk. There are two unknowns in the equation they are R and σ. Are they giving too much information?
 
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I have the two equations here how do I go about solving this. After substuiting E ,v and x for both equations I can divide the two equation by each other. Is there any easier way to do this. It is a homework problem I don't want to lose point please reply :)
E = 2k_e\pi\sigma(1-\frac{x}{\sqrt{x^2+R^2}})
V = 2k_e\pi\sigma\(x(\sqrt{1+\frac{R^2}{x^2}}-1)
 
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