Finding complex solutions from an eqn.

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The discussion revolves around finding complex solutions to the equation z^2 + conjugate(z^2) = 0, specifically when z = 1 + i. Participants express confusion over the relationship between the equation and the specific value of z, questioning whether the goal is to demonstrate that (1+i)^2 + (1-i)^2 equals zero or to solve for conjugate(z^2). The proposed approach involves manipulating the equation to isolate z^2, leading to z^2 = -1 + i. However, clarity is lacking on how to proceed with finding all complex roots and the implications of using the conjugate. The conversation highlights the complexities of solving equations involving complex numbers and their conjugates.
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Given z = 1 + i,

Find all complex solutions to z^{2} + Conjugate:z^{2} = 0

I have come up with a way to solving this but it doesn't make any sense.

would it be:
z^{2} + 1-i = 0

z^{2} = -1+i

Solve for all complex roots

then do the same for conjugate squared?
 
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JC3187 said:
Given z = 1 + i,

Find all complex solutions to z^{2} + Conjugate:z^{2} = 0

I have come up with a way to solving this but it doesn't make any sense.

would it be:
z^{2} + 1-i = 0

z^{2} = -1+i

Solve for all complex roots

then do the same for conjugate squared?

Finding all complex solutions to z^2+conjugate(z^2)=0 makes a bit of sense. Adding "when z=1+i" makes it make no sense unless you just want to show (1+i)^2+(1-i)^2=0. Or do you just want to solve (1+i)^2+conjugate(z^2)=0??
 
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