Finding density of a sphere and percentage error

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To find the density of a sphere with a diameter of 4 cm and a mass of 1.35 grams, the volume is calculated using the formula 4/3 x π x r³, resulting in approximately 33.51 cm³. The density is then determined by dividing the mass by the volume, yielding a density of about 0.040 g/cm³. To calculate the percentage error compared to the actual density of 7.87 g/mL, the formula involves subtracting the calculated density from the accepted density, dividing by the accepted density, and multiplying by 100, resulting in a percentage error of -99.50%. It's important to carry units through calculations to ensure consistency, as density is expressed in g/cm³. This method effectively illustrates how to calculate density and percentage error for a sphere.
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1. What is the Density in g / mL of a sphere with a diameter of 4 cm and a mass of 1.35 grams?

What is the percent error if the actual density of the sphere was 7.87 g / mL?



2.Volume= 4/3 x pie x r cubed
Density= mass/volume
percentage error= result minus accepted divided by acceptd multiplied by 100

3. 4/3 x pie x 2 (cubed) =33.510
1.35/33.510= .040
.040-7.87/7.87 x 100= -99.50
 
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Carry the units through in your calculation to make sure they match the desired units, in this case you will want to end up with a density expressed in g/mL. Notice that the units you end up with in your calculation for density is g/cm^3. Hope this helps.
 
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