Finding dimensions of a rectangle.

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Homework Help Overview

The problem involves finding the dimensions of a rectangle given its perimeter and a relationship between its length and width. The perimeter is stated to be 24 ft, with the length being 4 ft longer than the width.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss setting up equations based on the perimeter and the relationship between length and width. There are attempts to clarify the correct method for forming these equations, with some participants suggesting alternative approaches.

Discussion Status

Some participants have confirmed the calculations and expressed understanding of the equations involved. There is a recognition of different methods for solving the problem, with no explicit consensus on a single approach being necessary.

Contextual Notes

Participants question the necessity of adhering to a specific method for solving the problem, indicating a broader discussion on problem-solving techniques in mathematics.

rcmango
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Homework Statement



the perimeter of a rectangle is 24 ft. the length is 4 ft longer than the width find the dimensions

width x
length x+4

however, I should be doing it like this:

a first equation should start like: 2x+2y=?

and the second should start like x=y+?

so what's the length and the width?

Homework Equations





The Attempt at a Solution



x + x + (x+4)+(x+4) = 24
4x+8=24
-8 -8

4x = 16
4x/4 = 16/4

x = 4

so width 4 ft
and length 4+4, so 8 ft.
makes sense, since length should be greater than width.
 
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x + x + (x+4)+(x+4) = 24

x = 4

exactly
 
rcmango said:

Homework Statement



the perimeter of a rectangle is 24 ft. the length is 4 ft longer than the width find the dimensions

width x
length x+4

however, I should be doing it like this:

a first equation should start like: 2x+2y=?

and the second should start like x=y+?

so what's the length and the width?

Homework Equations





The Attempt at a Solution



x + x + (x+4)+(x+4) = 24
4x+8=24
-8 -8

4x = 16
4x/4 = 16/4

x = 4

so width 4 ft
and length 4+4, so 8 ft.
makes sense, since length should be greater than width.

Why do you say you "should be doing it like this:"? There is no *should*---any correct method is OK. Doing it two ways might be helpful towards learning goals, but it is not necessary for correct presentation of the solution.
 
If you've learned one way of solving problems of this kind, and you're expected to show that you have, in fact, understood the technique, then you probably should be doing just what you are, namely translating the facts bit by bit into equations, i.e.
  • "rectangle" suggests the equation 2x + 2y = 24
  • "width versus height" remark means y = x + 4
If you're just interested in the answer, any method will do, for instance this one, which I'll call "guess and revise":

Start with any width you like, say 7. Then the length will be 4 more, so 11. This gives you a perimeter of 7+7+11+11 = 36.

Oops, that's 12 too much. Let's subtract this "extra" length from the four sides, taking 12/4 = 3 away from each: width now is 7-3 = 4, and length is 11-3 = 8.
 
thankyou phinds for confirming.

Thanks for completing those equations Michael Redei, i seen them done that way and I didn't understand it, its much more clear now.
 
Last edited:

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