How do I Find the Dispersion Relation for a PDE?

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\imath\frac{\partial u}{\partial t} + \frac{\partial^2 u}{\partial x^2}=0

\left(x,t\right) = \int^{\infty}_{-\infty}A\left(k\right)e^{\imath\left(kx-wt\right)}dk

u\left(x,0\right)=\delta\left(x\right)

This is what I am working with. I am supposed to find the dispersion relation. So far I have gotten


A\left(k\right) = \frac{1}{2\pi}\int^{\infty}_{-\infty}\delta\left(x\right)e^{-\imath\left(kx\right)}dx = \frac{1}{2\pi}

plugging this into u(x,t) do I work with


u\left(x,t\right) =\frac{1}{2\pi}\int^{\infty}_{-\infty}e^{\imath\left(kx-wt\right)}dk

This is where I am stuck. I know w(k) is the dispersion relation. If I put in the pde do I just deal with

\imath \left(-\imath w\right) + \frac{d^{2}u}{dt^{2}} = w +\frac{d^{2}u}{dt^{2}}=0

not sure how to pull out the dispersion equation or if I am even going the right route. Any clues on how to proceed would be most appreciated. Solving this equation does not seem to get me to where I want to be. Thanks!
 
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Am I making this too hard on myself. I just saw a similar problem and according to this book I should just get

w-k^2=0\Rightarrow w=k^2

I figured this out I believe.
 
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You have:
<br /> i\frac{\partial u}{\partial t}+\frac{\partial^{2}u}{\partial x^{2}}dk<br />
Write:
<br /> u=\int_{-\infty}^{\infty}A(k)e^{i(kx-\omega (k)t)}<br />
So we just differentiate!
<br /> \frac{\partial u}{\partial t}=\int_{-\infty}^{\infty}(-i\omega (k))A(k)e^{i(kx-\omega (k)t)}dk,\quad\frac{\partial^{2}u}{\partial x^{2}}=\int_{-\infty}^{\infty}A(k)(-k^{2})e^{i(kx-\omega (k)t)}dk<br />
Insert the above into your equation to obtain the dispersion relation.
 
Is that dk a typo? Not sure what it is there for.

My professor said to just use

\phi\left(x,t\right)=A\left(k\right)e^\left(i\left(kx-wt\right)\right)

to find the dispersion relation, therefore leaving me with

w=k^2

and that the integral is just the "sum" of all the solutions.

Thanks for the help!
 
You have to integrate over all possible wavenumbers k, so when do the substitution as I suggested you can get everything to one side as:
<br /> \int_{-\infty}^{\infty}(\omega (k)-k^{2})A(k)e^{i(kx-\omega (k)t)}dk=0<br />
The only way for this integral to be zero of if the integrand is zero and hence you have your dispersion relation.
 
Ahhhh...makes sense now. Thank you for the clarification.
 
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