Finding distance from origin using acceleration

AI Thread Summary
The acceleration of a particle is given by a(t)=3ti+4tj, and the goal is to find its distance from the origin at t=2s. The user integrated the acceleration to find velocity as v(t)=(3t^2)/2i+2t^2j, and then integrated again to find position as x(t)=(t^3)/2i+(2t^3/3)j, resulting in a distance of 9.33 m. However, the correct approach involves calculating the magnitude of the vector, which requires using the square root of the sum of the squares of the components. After applying this method, the user found the distance to be approximately 6.67 m, aligning more closely with the teacher's expected answer of about 7 m. Understanding vector magnitudes is crucial in these calculations.
Entr0py
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Homework Statement


Acceleration of a particle that begins at rest at the origin is given by a(t)=3ti+4tj, where a is in m/s^2 and t is in seconds. The particle's distance from the origin at time t=2s is what?

Homework Equations


You need to find velocity then distance

The Attempt at a Solution


To find velocity I integrated the acceleration (I haven't covered integration in calculus yet, so it's a bit difficult to do). I got v(t)=(3t^2)/2i+2t^2j. Now to find distance I integrate velocity. I got x(t)=(t^3)/2i+(2t^3/3)j. Plugging in t=2 s, I get x=9.33 m. But my teacher says the answer is about 7 m.
 
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Entr0py said:
To find velocity I integrated the acceleration (I haven't covered integration in calculus yet, so it's a bit difficult to do). I got v(t)=(3t^2)/2i+2t^2j. Now to find distance I integrate velocity. I got x(t)=(t^3)/2i+(2t^3/3)j. Plugging in t=2 s, I get x=9.33 m. But my teacher says the answer is about 7 m.
You did fine with your integrations! But note that the result is a vector value with i and j components (or x and y components if you wish). How do you find the magnitude of a vector?
 
You would do the square root of the i and j hats right?
 
gneill said:
You did fine with your integrations! But note that the result is a vector value with i and j components (or x and y components if you wish). How do you find the magnitude of a vector?
And thank you for your response.
 
Entr0py said:
You would do the square root of the i and j hats right?
Square root of the sum of the squares. Like finding the hypotenuse of a right angle triangle. This is also called "adding in quadrature" if you're interested in the lingo.
 
Thank you man. I found the distance by finding the i and j hat separately. I got 4ti+(16/3)tj m. I plus in t=2 s and I get square root of 44.4. which is about 6.67 which is close to 7 m. Thanks a lot for helping me.
 
gneill said:
Square root of the sum of the squares. Like finding the hypotenuse of a right angle triangle. This is also called "adding in quadrature" if you're interested in the lingo.
You already know I'm interested in the lingo.
 
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