Finding dt/dθ with t2-1 = 2√(z2-1)exp(iθ)(z+√(z2-1)cosθ)

[aaaa202]

How do I most easily find dt/dθ, when they are related by the following equation:

t²-1 = 2√(z²-1)exp(iθ)(z+√(z²-1)cosθ)

and t = z + √(z²-1)exp(iθ)

I could find t and then differentiate, but with all the square roots it's going to be a mess. Also my teacher seemed to think it was easy, so therefore I ask what else can be done in a situation like this.

Thanks

 

[HallsofIvy]

I'm not clear what you mean here. You have two different equations defining s as a function of \theta (I presume z is to be treated as a constant.). And they are NOT equivalent.