Finding eigenvalues, Shankar exercise 1.8.3

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SUMMARY

The discussion centers on finding eigenvalues for the matrix \(\Omega = \begin{bmatrix} 2 & 0 & 0 \\ 0 & 3 & -1 \\ 0 & -1 & 3 \end{bmatrix}\). The correct eigenvalues are \(\omega_1 = 1\), \(\omega_2 = 1\), and \(\omega_3 = 2\). The confusion arose from a miscalculation involving the determinant, specifically missing a factor of one-half in the original problem statement. This oversight led to incorrect eigenvalue solutions of \(\omega = 2\) and \(\omega = 4\).

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First, I appologise if this is in the wrong place, while the book is QM, the question is pure maths. Also I'm not sure if this techically counts as homework as I am self studying. Finally, sorry for the poor formatting, I'm not that good with LaTeX

Homework Statement



Given the matrix: \Omega =
\left[ {\begin{array}{ccc}<br /> 2 &amp; 0 &amp; 0 \\<br /> 0 &amp; 3 &amp; -1 \\<br /> 0 &amp; -1 &amp; 3 \\<br /> \end{array} } \right]<br />

Show that \omega1 = \omega2 = 1; \omega3 = 2

Homework Equations


The Attempt at a Solution



So det(\Omega - \omegaI) = (2 - \omega)((3 - \omega)(3 - \omega) - 1)

Which obviously leaves \omega = 2, but also (3 - \omega)2 = 1, the solutions to which should be \omega = 2 and \omega = 4.

Where am I going wrong?

Any help greatfully appreciated.
 
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You're not going wrong for the given matrix. Are you sure you're doing the right problem?
 
You're absolutely right, there was a factor of a half in the original question that I completely missed, thanks. I must have checked the original problem a dozen times before posting and didn't spot it, I hate my brain sometimes.

Thanks again,

Tim
 

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