Finding Electric Field for Spherical Charge Distribution?

AI Thread Summary
To find the electric field for a spherical charge distribution with a varying charge density given by ρ(r) = Ke^{-br}, the total charge Q can be calculated using the integral of the charge density over the volume. The correct approach involves using the differential charge element dq = ρ * spherical jacobian, leading to dq = 4πKr²e^{-br}dr. The electric field E can then be derived from the total charge Q using E = kQ/r². The discussion clarifies that using the spherical integration differentials is essential for accurate results, and the method involving the spherical jacobian is preferred for consistency.
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Homework Statement


There is a charge density rho that exists in a spherical region of space defined by 0 < r < a.
\rho (r) = Ke^{-br}
How do you find the electric field if a charge density varies as such?

The Attempt at a Solution



I found Q total = \int \int \int \rho dV
Now I need to find E.

My real question is can I just put Q (as a function of r) into E = kQ/r^2? Or do I need to reevaluate the integral using dq = \rho r^2 sin(\theta) dr d\theta d\phi

I get two different answers, (and I would have thought they should be the same) so which method is correct? I would have thought either would work.
 
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What do you mean? Q is the integral of the charge density over the volume. Also, I think you mean dr = rho r^2 sin(\theta) dr d\theta d\phi. What did you do for your integral?
 
Why sin(\theta)? rho depends only on r so dQ = 4\pi Kr^{2}e^{-br}dr
 
Oh whoops, I shouldn't have had rho in there, and I missed it when you had it. You were right about the dq I was questioning. dq= rho *spherical jacobian (i.e. spherical integration differentials), which is what you had.

Yes, dQ = 4\pi Kr^{2}e^{-br}dr

This is the way you want to go. I don't really understand what other way you would have gone about it.
 
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