Finding Electric Flux of a Disc of Radius r

[prasum]

a disc of radius r we have to find electric flux at a point which is at a distance r from the centre



i have used e=(sigma/2eo)(1-x/sqrt(r^2+x^2)) the area da=2pir*dr

i know flux=closed integral (e.da)
and x=r

after that what should i do
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[ashishsinghal]

r from the center in which direction? Is it along the axis? also since flux is a closed integral, flux at any point does not make sense. Electric field will be more appropriate...

 

[prasum]

r from the center in which direction? Is it along the axis? also since flux is a closed integral, flux at any point does not make sense. Electric field will be more appropriate...

yes it is along axis

 

[ashishsinghal]

you haven't answered whole of my question. Is it really flux what you are talking about as flux is for a closed surface.
Also if it was flux then since it is just a point with no charge by gauss law, flux would be zero.
It has to be field.

 

[prasum]

you haven't answered whole of my question. Is it really flux what you are talking about as flux is for a closed surface.
Also if it was flux then since it is just a point with no charge by gauss law, flux would be zero.
It has to be field.

the point is a charged particle

 

[cupid.callin]

the point is a charged particle

is it a ring or a point charge?
flux or field?
if flux .. what is the surface?

please correct your question and post again ...


@ Ashish

how was your JEE?

 

[prasum]

is it a ring or a point charge?
flux or field?
if flux .. what is the surface?

please correct your question and post again ...


@ Ashish

how was your JEE?

it is point charge

 

[prasum]

it is point charge

and flux

 

[cupid.callin]

so what is the surface?>?

flux is always for a surface

anyway if you are asking for flux due to point charge on a spherical surface of radius r and centerd at the charge then its \frac{q}{\epsilon_o}