Finding Equilibrium Forces in a Two-Member Frame

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The discussion focuses on solving for the forces in a two-member frame supporting a 200-lb cylinder and a 500 lb-ft couple moment. The user initially calculates forces on members AC and CB but struggles with the vertical force at point A, which is expected to be 175 lbs according to the textbook. It is noted that the couple moment was not considered in the calculations, leading to the incorrect result. Participants suggest summing external forces and moments to properly account for all forces, including the roller support reaction. The user realizes the need to incorporate the roller's reaction into the free body diagram for accurate results.
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Homework Statement



The two-member frame (see picture attached) supports the 200-lb cylinder and 500
lb–ft couple moment. Determine the force of the roller at B on member
AC and the horizontal and vertical components of force which the pin at
C exerts on member CB and the pin at A exerts on member AC. The
roller C does not contact member CB.


Homework Equations





The Attempt at a Solution


I split the frame into members AC and CB. The I found the forces acting on D(pulley) which gave me Dx = 200 lb and Dy = 200 lb. I plugged this into member CB; giving me the next equations:
ƩFx = 0: Cx +Bx -200 = 0
∴ Cx + Bx = 200

ƩFy = 0: Cy - 200 = 0
∴ Cy = 200

ƩMc = 0: 200(4) - 4Bx = 0
∴ Bx = 200 which also give me Cx = 0 from the summation of Forces in the x direction.
Then I plug the relevant values of Cx, Cy and Bx into the AC member; this gives me the following equations:
ƩFx = 0: Ax - Bx + 200(from cable) = 0
∴ Ax = 0

ƩFy = 0: Ay - 200 = 0
∴ Ay = 200
The issue that I am having is that this last answer is wrong according to the book. Its supposed to be Ay = 175 lbs. I know I didn't use the couple moment at all so, maybe this is the reason? But I really don't see how it could be 175 lbs. Any help would be greatly appreciated.
 

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rico22 said:

Homework Statement



The two-member frame (see picture attached) supports the 200-lb cylinder and 500
lb–ft couple moment. Determine the force of the roller at B on member
AC and the horizontal and vertical components of force which the pin at
C exerts on member CB and the pin at A exerts on member AC. The
roller C does not contact member CB.


Homework Equations





The Attempt at a Solution


I split the frame into members AC and CB. The I found the forces acting on D(pulley) which gave me Dx = 200 lb and Dy = 200 lb.
this is ok
I plugged this into member CB; giving me the next equations:
ƩFx = 0: Cx +Bx -200 = 0
∴ Cx + Bx = 200

ƩFy = 0: Cy - 200 = 0
∴ Cy = 200
No you cannot just isolate CB without including the pulley forces and torque.
The issue that I am having is that this last answer is wrong according to the book. Its supposed to be Ay = 175 lbs. I know I didn't use the couple moment at all so, maybe this is the reason?
well it has to factor in somewhere, right?
But I really don't see how it could be 175 lbs.
It is.
Any help would be greatly appreciated.
Before pulling the frame apart, try summing external forces = 0 and summing moments of external forces about A = 0. Only the cylinder weight and couple and reactions at A and C are external to the system.
 
Thank you for the reply. So if I take the entire frame would C then become a roller and not a pin?
 
ok I got it now... I was supposed to plug in the roller support reaction into the FBD of AC on top of Cy and Cx...that was throwing the whole thing off... thanks again.
 
You are missing the normal reaction because of the roller.
Link to the solution.
https://faculty.uca.edu/njaustin/ENGR2311/Quizzes/quiz07.pdf

Good job guyz. Enjoy.
 
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