Finding factors in order to use U sub

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SUMMARY

The discussion focuses on the integration of the function \(\int \frac{x}{\sqrt{x^2+x+1}}~dx\) and the method of completing the square to simplify the expression. The quadratic in the denominator, \(x^2 + x + 1\), is transformed into \((x + \frac{1}{2})^2 + \frac{3}{4}\), facilitating the integration process. The participants confirm that this method is systematic rather than reliant on trial and error or intuition.

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Homework Statement




\displaystyle{\int}\dfrac{x}{\sqrt{x^2+x+1}}~dx =<br /> <br /> \displaystyle{\int}\dfrac{(x+\frac 1 2)-\frac 1 2}{\sqrt{(x+\frac 1 2)^2+(\frac {\sqrt 3} 2)^2}}~dx

Homework Equations



Given.

The Attempt at a Solution



The solution is given, but I'm not sure how it was found. Is there a method for finding those factors or is it trial and error/intuition?
 
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TheKShaugh said:

Homework Statement




\displaystyle{\int}\dfrac{x}{\sqrt{x^2+x+1}}~dx =<br /> <br /> \displaystyle{\int}\dfrac{(x+\frac 1 2)-\frac 1 2}{\sqrt{(x+\frac 1 2)^2+(\frac {\sqrt 3} 2)^2}}~dx

Homework Equations



Given.

The Attempt at a Solution



The solution is given, but I'm not sure how it was found. Is there a method for finding those factors or is it trial and error/intuition?
There is a method. They are completing the square in the quadratic in the denominator.
x2 + x + 1 = x2 + x + (1/4) + (1 - 1/4)
= (x + 1/2)2 + 3/4
= (x + 1/2)2 + (√(3)/2)2

Then they are working with the numerator to get it as you see it in the expression on the right of what you posted.
 
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