Finding failure of a beam system

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To calculate the load that will produce failure in the beam system, the small beam can be treated as a cantilever beam subject to pure bending. The maximum stress formula is given as σmax = 6M / (h^3), where σmax equals the yield stress of the material, M is the moment, and h is the height of the beam's cross-section. By rearranging the formula, the maximum load can be determined using Fmax = (σmax * h^3) / (6*L), where L is the length of the beam. This approach provides a clear method for predicting failure based on material properties and dimensions. Understanding these calculations is crucial for ensuring structural integrity.
Jim Newt
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See attached for a picture.

I want to calculate the load that will produce a failure at the point in the picture. If I know all the required dimensions and material properties, how do I go about calculating the load that will produce failure? Thanks!

Jim
 

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What if you treat the small beam member to the right as a cantileaver beam? Any thoughts?
 
All right, how about this:

The small beam on the right is subject to pure bending, with a square cross section and the larger beam on the left is now just a wall that the small beam is attached to. So for a predicted failure model:

σmax = 6M / (h^3)

where we could set σmax = yield stress of the material
M = Fmax * L
L = beam length
h = height of square cross section

Rearranging, I get:

Fmax = (σmax * h^3) / (6*L)

What do you think of this?
 
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