Finding Final Velocities in a Two-Dimensional Collision

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In a two-dimensional collision problem, a 5.0-gram particle moving at 60 m/s collides with a stationary 2.0-gram particle, with both particles moving at a 30° angle post-collision. The conservation of momentum equations for both x and y components are essential to solve for the final velocities. The x-component equation is m1v1i = m1v1fcos(theta) + m2v2fcos(phi), while the y-component equation is 0 = m1v1fsin(theta) - m2v2fsin(phi). The discussion highlights the importance of using both equations to find the unknown final velocities accurately. The solution process involves substituting values and solving for the final velocities of the particles.
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Homework Statement



A 5.0-gram particle moving 60 m/s collides with a 2.0-gram particle initially at rest. After the collision each of the particles has a velocity that is directed 30° from the original direction of motion of the 5.0-gram particle. What is the speed of the 2.0-gram particle after the collision?

Homework Equations



conservation of kinetic energy equation
conservation of linear momentum equation and the x and y components

m1v1i=m1v1fcos(theta) + m2v2fcos(phi)

The Attempt at a Solution



m1=5
m2=2
m2=.4m1

theta=30
phi=30

Since the the only two variables I am missing are the two final velocities, I have tried solving one of the equations for mass2s final velocity and then subsituting that value into either the original equation or another one. Everytime i end with an answer that is not one of my choice. I am confused as to how i should go about find the final velocities.
 
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wesDOT said:
conservation of linear momentum equation and the x and y components

m1v1i=m1v1fcos(theta) + m2v2fcos(phi)
That's good for the x-components. What about the y-components? (That will give you the second equation needed.)
 
Doc Al said:
That's good for the x-components. What about the y-components? (That will give you the second equation needed.)

0=m1v1fsin(theta)-m2v2fsin(phi) right?
 
wesDOT said:
0=m1v1fsin(theta)-m2v2fsin(phi) right?
Right!
 
Thanks a lot. That has been taunting me all day. I tried everything else but that. Yet that was so simple. Again, thank you.
 
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