What focal length is needed for a 0.60x magnification with a diverging lens?

  • Thread starter Taylor Marks
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In summary, to produce a magnification of 0.60x on an object located 1.40 meters away, a diverging lens needs a focal length of 1.42 meters. This can be calculated using the equations M=hi/ho, 1/do + 1/di = 1/f, and M= -di/do.
  • #1
Taylor Marks
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Homework Statement


What focus is needed for in order for a diverging lens to produce a magnification of 0.60x on an object located 1.40 meters away?

Homework Equations


M=hi/ho
1/do + 1/di = 1/f
M= -di/do

The Attempt at a Solution


-di / 1.4 = 0.6
1/1.4 + 1/.84 =1/f
-di=0.84
1.42
 
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  • #2
Taylor Marks said:

Homework Statement


What focus is needed for in order for a diverging lens to produce a magnification of 0.60x on an object located 1.40 meters away?

Homework Equations


M=hi/ho
1/do + 1/di = 1/f
M= -di/do

The Attempt at a Solution


-di / 1.4 = 0.6
1/1.4 + 1/.84 =1/f
-di=0.84
1.42
Is that + sign correct?
 
  • #3
Just a small remark - rather say what focal length is needed...
 

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