Finding Force Constant of Spring: 0.296 kg & 3.3 J

AI Thread Summary
To find the force constant of a spring with a 0.296 kg mass and a total energy of 3.3 J, the correct formula involves the period T, which is given by T = 2π√(m/k). The user initially used an incorrect equation, leading to an erroneous calculation of k. The correct approach requires rearranging the formula to isolate k and substituting the known values accurately. Additionally, checking units throughout the calculation can help identify mistakes. Proper application of these principles will yield the correct force constant in N/m.
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Homework Statement


A 0.296 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.18 s. The total energy of the system is 3.3 J. Find the force constant of the spring. Answer in units of N/m.

Homework Equations


k=m(t/2\pi)^2

The Attempt at a Solution


k=296(0.18/2\pi)^2
I get 0.0002429276699 but it is wrong. Any ideas what i did wrong?
 
Last edited:
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Your equation is wrong. The period should be T = 2pi times the square root of (m/k). I believe that your equation has (k/m) instead of (m/k). Hope that helps.
 
Note also: you should learn the trick of carrying through your units and checking them... that would have helped you find this error.
 
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