Finding force(N) wood has against the bullet

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The discussion revolves around calculating the force exerted by a block of wood on a bullet that penetrates it. The bullet, weighing 1.80 g and traveling at 320 m/s, penetrates the wood to a depth of 0.140 m, leading to an acceleration of -365714.29 m/s². The calculated force is approximately 658 N, considering the opposite direction of forces between the bullet and wood. An alternative method suggested involves using the work-energy principle, where the force can be derived from the kinetic energy lost by the bullet divided by the distance penetrated. The conversation emphasizes the importance of significant figures in the final answer.
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Homework Statement



22.0-caliber rifle bullet of mass 1.80 g, traveling at 320 m/s strikes a block of soft wood, which it penetrates to a depth of 0.140 m. The block of wood is clamped in place and doesn't move. Assume a constant retarding force.

What force, in Newtons, does the wood exert on the bullet?

Homework Equations


The Attempt at a Solution

Long story short, acceleration is -365714.29 m/s^2

Is it really as simple as .0018*-365714.29 = -658.29 N ? Or maybe 658.29 N since the force of the wood on the bullet is opposite of the bullet on the wood?

Since Fnet = ma
 
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Crusaderking1 said:

Homework Statement



22.0-caliber rifle bullet of mass 1.80 g, traveling at 320 m/s strikes a block of soft wood, which it penetrates to a depth of 0.140 m. The block of wood is clamped in place and doesn't move. Assume a constant retarding force.

What force, in Newtons, does the wood exert on the bullet?


Homework Equations





The Attempt at a Solution




Long story short, acceleration is -365714.29 m/s^2

Is it really as simple as .0018*-365714.29 = -658.29 N ? Or maybe 658.29 N since the force of the wood on the bullet is opposite of the bullet on the wood?

Since Fnet = ma

It is that simple [I hope you a value is correct; I haven't checked]

The question referred to a retarding force, so easiest just to answer "The retarding force is 658N" watch the significant figures in your final answer - you use all the figures i your calculations]
 
Crusaderking1 said:
Long story short, acceleration is -365714.29 m/s^2

Is it really as simple as .0018*-365714.29 = -658.29 N ? Or maybe 658.29 N since the force of the wood on the bullet is opposite of the bullet on the wood?

Since Fnet = ma
You might find it easier to use energy: the work done by the wood on the bullet is equal to the loss of kinetic energy. So:

F = KE/d

AM
 
PeterO said:
It is that simple [I hope you a value is correct; I haven't checked]

The question referred to a retarding force, so easiest just to answer "The retarding force is 658N" watch the significant figures in your final answer - you use all the figures i your calculations]

Thanks.
 
Andrew Mason said:
You might find it easier to use energy: the work done by the wood on the bullet is equal to the loss of kinetic energy. So:

F = KE/d

AM

Never thought about that! thanks, that would make it easier.
 
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