Finding friction force *without* mass or coefficient

AI Thread Summary
A car coasting at 50 mph comes to a stop over 150 feet, prompting a discussion on calculating the friction force without knowing the car's mass or coefficient of friction. The initial velocity was converted to 22.35 m/s, and the acceleration calculated as -5.24 m/s². Participants noted that the problem lacks mass information, which is essential for determining the friction force directly. Suggestions included expressing the answer in terms of the car's weight, as the mass is not provided in the problem statement. The conversation emphasizes the importance of clarity in problem statements for physics calculations.
Amy G.
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Homework Statement


A car moving at 50mph coasts to a stop while traveling a distance of 150ft on level ground. what is the size of the friction force needed to bring this car to rest?

Homework Equations


vf^2 = vo^2 + 2a(xf-xo)
F=ma
Fk=un[/B]

The Attempt at a Solution


I first converted everything to meters and seconds.
So, initial velocity is 22.35 m/s and distance traveled is 47.7 meters.
Then, I found acceleration, which is -5.24 m/ss.
Then, I found time. 4.27 seconds

I tired to find the coefficient of friction with:
F=ma=u(mg) (n is the same as mg because the surface is level)
ma=u(mg)
a=ug
-5.24=u(-9.8)
u=0.53

I have no idea what to do now. It wants the friction force, not the coefficient.
those are pretty much the only formulas we have at this point. We haven't gotten to work or energy formulas.
 
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Amy G. said:

Homework Statement


A car moving at 50mph coasts to a stop while traveling a distance of 150ft on level ground. what is the size of the friction force needed to bring this car to rest?

Homework Equations


vf^2 = vo^2 + 2a(xf-xo)
F=ma
Fk=un[/B]

The Attempt at a Solution


I first converted everything to meters and seconds.
So, initial velocity is 22.35 m/s and distance traveled is 47.7 meters.
Then, I found acceleration, which is -5.24 m/ss.
Then, I found time. 4.27 seconds

I tired to find the coefficient of friction with:
F=ma=u(mg) (n is the same as mg because the surface is level)
ma=u(mg)
a=ug
-5.24=u(-9.8)
u=0.53

I have no idea what to do now. It wants the friction force, not the coefficient.
those are pretty much the only formulas we have at this point. We haven't gotten to work or energy formulas.

I agree that the force needed will depend on the mass of the car. Are you sure that is the whole problem statement? Can you post a (clear) picture or screenshot of the problem statement that you were given?
 
berkeman said:
I agree that the force needed will depend on the mass of the car. Are you sure that is the whole problem statement? Can you post a (clear) picture or screenshot of the problem statement that you were given?

I tried, but can't do it. I have photographs of it and my work saved on my computer but I can't upload them on here. I don't really have any place on the internet where I keep pictures either

I looked at it again though, and it definitely says that :frown:
 
Amy G. said:
I tried, but can't do it. I have photographs of it and my work saved on my computer but I can't upload them on here. I don't really have any place on the internet where I keep pictures either

I looked at it again though, and it definitely says that :frown:

I'll PM you my e-mail address, in case you can e-mail them to me and I can post them for you.
 
Maybe all they want is the force in g's.

Chet
 
Chestermiller said:
Maybe all they want is the force in g's.

Chet

Yeah, that's kind of what I'm guessing now. There certainly is no mention of the car's mass in the problem statement, so I guess it just needs to show up in the answer as Amy did...

PF Amy Problem.jpg


PF Amy Work.jpg
 
BTW, Amy -- your files were JPG files, so you should be able to click the UPLOAD button in the Reply window to upload a *lJPG file as an attachment.

Also, we usually do not want your work to be an image, and prefer that you type it into the PF directly. Just a note for future posts... :smile:
 
Your answer could be expressed as "some specific fraction of the magnitude of the car's weight."
 
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