Finding Indefinite Integral of a combination of hyperbolic functions

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SUMMARY

The integral of the function \(\int \frac{cosh(x)}{cosh^2(x) - 1}\,dx\) can be simplified using the identity \(cosh^2(x) - 1 = sinh^2(x)\). This transformation allows the integral to be rewritten as \(\int coth(x)csch(x)\,dx\). The final solution is \(-csch(x) + C\), where \(C\) is the constant of integration. The substitution \(u = tanh(\frac{x}{2})\) suggested by WolframAlpha is not necessary for solving this integral.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically \(cosh(x)\) and \(sinh(x)\)
  • Knowledge of integration techniques, particularly substitution and identities
  • Familiarity with the definitions of \(coth(x)\) and \(csch(x)\)
  • Basic calculus concepts, including the integral of hyperbolic functions
NEXT STEPS
  • Study hyperbolic function identities and their applications in integration
  • Learn advanced integration techniques, focusing on substitution methods
  • Explore the properties and graphs of hyperbolic functions for better visualization
  • Practice solving integrals involving hyperbolic functions to reinforce understanding
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Students studying calculus, particularly those focusing on integration techniques involving hyperbolic functions, as well as educators looking for examples of hyperbolic function integrals.

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Homework Statement



Compute the following:

\int \frac{cosh(x)}{cosh^2(x) - 1}\,dx


Homework Equations


\int cosh(x)\,dx = sinh(x) + C


The Attempt at a Solution


I had no clue where to start, so I went to WolfRamAlpha, and it used substitution but it made u = tanh(\frac{x}{2}) and I had no clue how I am supposed to know to do that.

Any advice on where to start is greatly appreciated.
 
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I solved this problem after realizing that cosh^2(x) - 1 = sinh^2(x). This allowe me to split make it \int coth(x)csch(x)\,dx, and then I could use another identity to set that equal to -csch(x) + c
 

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