Finding Initial Speed Given Range

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Homework Help Overview

The discussion revolves around determining the initial speed required for a projectile launched from a catapult to achieve a specified range of 0.67 km. The subject area pertains to projectile motion and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for additional information, such as the launch angle, to solve the problem. There are references to equations related to projectile motion, including the maximum range formula and the relationship between angle and range. Some participants express uncertainty about the derivation of these equations.

Discussion Status

The discussion is active, with participants exploring different equations and concepts related to projectile motion. Some guidance has been offered regarding the conditions for maximum range and the importance of understanding the underlying principles rather than just memorizing formulas.

Contextual Notes

There is a noted lack of information regarding the launch angle, which is critical for solving the problem. Participants also mention the assumption that the initial and final heights are the same for the equations being discussed.

reigner617
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Homework Statement


If you want to use a catapult to throw rocks, and the max range is 0.67 km, what initial speed must the rocks have as they leave the catapult?

Homework Equations



v=Δr/Δt

The Attempt at a Solution


I sketched a graph of the projectile trajectory with the desired range on the x-axis. I also converted 0.67 km to 670 m. I concluded that acceleration would be -9.8 m/s. I couldn't go any further since I feel like I am not given enough information to work with.
 
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I feel like I am not given enough information to work with.
... you need to know the angle the stones are launched at - you are told this though. The way the question is written suggests you have already derived or had given to you a bunch of equations for range, max-height and so on. If not, then try sketching velocity-time graphs for the horizontal and vertical components of the motion.

note: the acceleration is -9.8m/s/s in the +y direction, taking +y to be "upwards".
 
Thank you for the quick response. I used the formula Rmax=V02/g. After substituting the givens into the formula, I came up with 81 m/s
 
Did you understand where the equation came from?
 
Not quite, although a similar formula that I know is R=(V0^2)sin(2t)/g
 
I also understand that for the range to be max, the angle has to be 45, and if we put 45 into the V0^2sin(2t)/g formula, sin2t would just be 1, and we are left with just V0^2/g
 
reigner617 said:
Not quite, although a similar formula that I know is R=(V02)sin(2θ)/g ... I also understand that for the range to be max, the angle has to be 45, and if we put 45 into the V02sin(2t)/g formula, sin2θ would just be 1, and we are left with just V02/g
... well done :)

I just don't like the style of teaching that has students memorize a bunch of equations.
Note: that equation only works where the initial and final heights are the same - when you can derive the equations from velocity-time graphs you'll be able to do any ballistics problem, and many more besides, without having to memorize or look up any equations ... so it's a skill worth obtaining.
 

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