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Finding intersection of vector subspaces

  1. Oct 16, 2011 #1
    1. The problem statement, all variables and given/known data

    What are the intersections of the following pairs of subspaces?
    (a) The x-y plane and the y-z plane in R'.
    (b) The line through (1, 1, 1) and the plane through (1,0, 0) and (0, 1, 1).
    (c) The zero vector and the whole space R'.
    (d) The plane S perpendicular to (1, 1, 0) and perpendicular to (0, 1, I) in R3
    What are the sums of those pairs of subspaces?

    2. Relevant equations



    3. The attempt at a solution

    So I've been using logic, but I don't know if what I'm doing is right or makes sense...

    a) I think the intersection is the y-axis (it's where the two planes I believe meet). And for the sum I have that R3= x-axis + y-axis+z-axis that can be written as a combination of a member of the xy- and yz-planes. So, R3=xy-plane_yz-plane

    b) In 3D, a line is either parallel to a plane or intersects it in a single point. So, I'm thinking it should intersect at the single point (1,1,1) and that the sum should be the plane through (1,0,0) and (0,1,1), but I'm a bit at a loss here...

    c) The intersection I think should be the lonely zero vector and their sum I think is the whole space R3.

    d) This one I'm completely lost!

    Can anyone please help me, particularly with parts B and D, and let me know if my logic seems right?

    Thanks!!!
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 16, 2011 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    What is R'? You seem to mean R3.
    Yes, that is correct.

    No, that is not true. There are three possibilities. A line may per parallel to a plane (no points in common), intersect it in a single point (one point in common), or lie in the plane (an infinite number of points in common- all points on the line).

    Look again. The origin, of course, and the point (1, 1, 1) are both in the plane containing (0, 0, 0), (1, 0, 0), and (0, 1, 1). (Remember that we are talking about subspaces so they must contain (0, 0, 0) and the plane must contain (1, 0, 0)+ (0, 1, 1).)

    Yes, that is correct.

    I don't understand what you mean by "The plane S perpendicular to (1, 1, 0) and perpendicular to (0, 1, I) in R3". I assume you meant (0, 1, 1) rather than (0, 1, I), but you only refer to a single space, S. Of course, a plane perpendicular to (1, 1, 0) cannot be also perpendicular to (0, 1, 1)! So I think you mean "The plane S perpendicular to (1, 1, 0) and the plane T perpendicular to (0, 1, 1)."
    Recall, from Calculus, that a plane perpendicular to vector <A, B, C> containing [itex](x_0, y_0, z_0)[/itex] can be written as [itex]A(x- x_0)+ B(y- y_0)+ C(z- z_0)= 0[/itex]. That is, plane S (which must contain (0,0,0) to be a subspace) is x+ y= 0 while T is y+ z= 0. Those say y= -x and z= -y= x. Thus, taking x= t as parameter, the intersection of the two planes is the line x= t, y= -t, z= t. <x, y, z>= <t, -t, t>= t<1, -1, 1>.
    The sum of two two distinct two dimensional subspaces is always a three dimensional space.

     
  4. Oct 16, 2011 #3
    Yes I did mean R3. Thank you!

    For part b:

    I see now. So, because (1,0,0) + (0,1,1) = (1,1,1) can be written as a linear combination, it is obviously a subspace. And then the intersection would be the line, not the point, going through (1,1,1). And then the sum should be the plane through (1,0,0) and (0,1,1).

    Am I thinking correctly now?


    For part d:

    This is why I am so confused. The problem states "The plane S perpendicular to (1,1,0) and perpendicular to (0,1,1) in R3. I too was thinking they should be two separate planes. I'm lost!
     
  5. Oct 16, 2011 #4
    So I'm thinking that for part d, it must refer to two separate planes because the main question asks for the intersection of the following PAIRS of subspaces. It's the only way I think makes sense.
     
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