Finding Inverse Laplace Transform with Fractional Powers and Convolution

Sol-chan
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Homework Statement

Find the inverse laplace transform of:

1/(s-2)3 + 25/(s+1)(s-2)2 + s/(s-2)2


The attempt at a solution

I get (1/2)e2tt2 + (25/7)e-t-(25/7)e2t+(75/7)te2t for the first two, but I'm not even sure where to start for s/(s-2)2. I was thinking it might use convolution, but I'm not sure that I understand how convolution works... I'd really just like a hint to get me started on it...
 
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1/(s-2)2 looks like a shifted form of 1/s2, so you want to write numerator in terms of (s-2), i.e. s = (s-2)+2.
 
Okay, so then I would have (s-2)/(s-2)2 + 2/(s-2)2

which is 1/(s-2) + 2/(s-2)2

so then I'd get e2t + 2e2tt
 
That's right. You may want to check your algebra on your earlier work. Mathematica gets a different answer than you do.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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