Finding Length of a Pendulum from Kinetic Energy

  • Thread starter Thread starter Dante Tufano
  • Start date Start date
  • Tags Tags
    Pendulum
AI Thread Summary
The discussion revolves around finding the length of a pendulum using its kinetic energy and potential energy. The user initially calculated the height from kinetic energy but struggled to connect it to the pendulum's length. They were guided to use the conservation of energy principle, equating maximum kinetic energy to potential energy at a height related to the angle θ. After recalculating, the user resolved their algebra mistake and found the correct values. The conversation emphasizes the importance of careful calculations in applying physics principles.
Dante Tufano
Messages
32
Reaction score
0
Okay, so here's the question:

The figure below shows the kinetic energy K of a simple pendulum versus its angle θ from the vertical. The pendulum bob has mass 0.320 kg. What is the length of the pendulum?

W0353-N.jpg


Equations: KE=(mv^2)/2
U=mgh
x(t)=xmcos(wt+phi)

I solved for the height by setting the max kinetic energy equal to the max potential energy, and got .004783, but I have no idea how to use the position equation to find the max velocity or what to do after that. Could I please get some guidance?
 
Physics news on Phys.org
when the pendulum is in it's mean position, you know that the KE is maximum.

So, find the velocity there. Then use the conservation of energy principle assuming that that the pendulum bob rises to a height L(1-cosθ). substituting v in that equation you get

L(1-cosθ) is equal some value. You know θ when KE becomes 0 from the graph.
substitute that.
 
Okay, so I solve for the velocity using the max kinetic energy and have a max velocity of .3062 m/s. I set L(1-cosθ) equal to (KEmax/mg) and solved for L using the θ value .1. However, I got the wrong answer, so can I get any more clues as to what I'm doing wrong?
 
Sorry, I made an algebra mistake! The values came out write after I punched them in again. Thanks a lot!
 
oh, haha
happy to help. :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
15
Views
1K
Replies
11
Views
2K
Replies
21
Views
2K
Replies
4
Views
2K
Replies
31
Views
3K
Replies
3
Views
2K
Back
Top