Finding Lengths of Springs with Three Identical Masses

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Homework Help Overview

The problem involves three identical masses, each weighing 6.00 kg, suspended by three identical springs with a force constant of 8.50 kN/m. The original length of each spring is 11.0 cm. Participants are tasked with determining the length of each spring when the masses are attached.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss isolating the bottom mass and treating the system of masses in various configurations. There are attempts to apply the equations of motion and spring force, with some participants questioning the correctness of their calculations and the conversion of units.

Discussion Status

Some participants have shared their calculated lengths for the springs, while others are seeking clarification on the application of unstretched lengths and how they affect the calculations. There is an ongoing exploration of the assumptions regarding the system's setup and the interpretation of the spring constants.

Contextual Notes

Participants note the importance of the unstretched length of the springs in their calculations, with some confusion regarding how many unstretched lengths should be added for each spring based on their respective positions in the system.

Moninder
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Homework Statement



Three identical 6.00kg masses are hung by three identical springs, as shown in the figure. Each spring has a force constant of 8.50kN/m and was 11.0cm long before any masses were attached to it. How long is each spring when hanging as shown? (Hint: First isolate only the bottom mass. Then treat the bottom two masses as a system. Finally, treat all three masses as a system.)

Homework Equations


F=-ma
F=-kx

The Attempt at a Solution


I started with the bottom block.
-ma=-kx
(6.00kgx9.8m/s^2)/-(8.50kN/m)=x
x=6.92m? and then i added 0.11m
and its still wrong
I also took the F=ma and divided by 1000 to get into(0.0588) kN and then divided it by 8.50kN and then dded .11m and still wrong

I need to find all three block eventually
 
Last edited:
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That can't be answered without the diagram.
 
This is how it is from top to bottom
Ceiling
-
spring
-
block
-
spring
-
block
-
spring
-
block
 
Moninder said:

Homework Statement



Three identical 6.00kg masses are hung by three identical springs, as shown in the figure. Each spring has a force constant of 8.50kN/m and was 11.0cm long before any masses were attached to it. How long is each spring when hanging as shown? (Hint: First isolate only the bottom mass. Then treat the bottom two masses as a system. Finally, treat all three masses as a system.)

Homework Equations


F=-ma
F=-kx


The Attempt at a Solution



I also took the F=ma and divided by 1000 to get into(0.0588) kN and then divided it by 8.50kN and then dded .11m and still wrong

What was your answer from doing the calculation this way, and how do you know it was wrong?
 
For the bottom spring I got 0.1169m
Middle Spring 0.3376m
Top spring 0.35075m

I put it in an online program
 
Still need help
 
Moninder said:
I started with the bottom block.
-ma=-kx
(6.00kgx9.8m/s^2)/-(8.50kN/m)=x
x=6.92m?
Note that the spring constant is in kN/m, not N/m.
 
Doc Al said:
Note that the spring constant is in kN/m, not N/m.

Yes I know, check my 3 answers i posted, they are with converting the kN
 
Moninder said:
For the bottom spring I got 0.1169m
Looks OK.
Middle Spring 0.3376m
Top spring 0.35075m
Show how you got these last two.
 
  • #10
Doc Al said:
Looks OK.

Show how you got these last two.

I added the weights together
Mg=kx
((6+6)9.8)/(8500N/m) + .22 m =middle spring
Top spring
((6+6+6)9.8)/(8500N/m) + 0.33m
 
  • #11
Moninder said:
I added the weights together
Mg=kx
((6+6)9.8)/(8500N/m) + .22 m =middle spring
Top spring
((6+6+6)9.8)/(8500N/m) + 0.33m
Ah... But they all start with an unstretched length of 0.11m.
 
  • #12
Doc Al said:
Ah... But they all start with an unstretched length of 0.11m.

Yes, i did add in the unstrecthed length?
 
  • #13
Moninder said:
Yes, i did add in the unstrecthed length?
For the middle spring you added in twice the unstretched length; for the top spring you added three times the unstretched length.

Each spring has a total length equal to its unstretched length (0.11m for each) plus the amount of stretch (which varies).
 
  • #14
Why would i not add in 2 lengths because the middle spring is also carrying the bottom spring
 
  • #15
Moninder said:
Why would i not add in 2 lengths because the middle spring is also carrying the bottom spring
How does that affect its unstretched length?
 
  • #16
Oh now i get it, i should just only add in 1 unstrecthed length because I am only calculating for 1 spring
 
  • #17
Moninder said:
Oh now i get it, i should just only add in 1 unstrecthed length because I am only calculating for 1 spring
Right.
 
  • #18
Thank you
 

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