Finding Mass: Calculating Friction & Motion

AI Thread Summary
To determine when the copper block will start to slip on the steel turntable, the problem involves calculating forces using Newton's second law and the coefficient of static friction. The normal force is equal to the weight of the block, which is expressed as N = mg. The frictional force can be calculated using Ff = μN, where μ is the coefficient of static friction (0.53). However, without knowing the mass of the block, it is impossible to calculate the exact time interval for slipping to occur. The discussion emphasizes the need to find the mass to solve the problem accurately.
chenny
Messages
8
Reaction score
0
A copper block rests 30.cm from the center of a steel turntable. The coefficient of static friction between the block and the surface is .53. The turntable starts from rest and rotates with a constant angular acceleration of .50 rad/s^2. After what time interval will the block start to slip on the turntable.
Hint: The normal force in this case equals the weight of the block.



Fc=u(mew)timesN



Tangential Speed = .15m/s
mew =.53
N = mg
N = m(9.81 m/s^2)

How do I find the mass?


Please and Thank you...
 
Physics news on Phys.org
Hi chenny,

This is a rotational motion problem. By Newton's 2nd law, Net force= ma. F- Ff = ma. Since tangential acceleration = radius x angular acceleration, F- Ff = m (0.3m x 0.5 rad/s²). When block starts to slip, Ff = (meu)N = 0.53mg. Manipulate Newton's 2nd law, u get F = ma = m dv/dt and solve for t. But u cannot find the mass of the block, thus u cannot find the time when block starts to slip on turntable.

How to find the mass of the block?? Can someone pls help us??
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top