Finding mass of spring from time period.

AI Thread Summary
The discussion focuses on determining the mass of a spring using the time period squared (T^2) graph against the attached block mass (M). The practical handbook provides a formula that includes variables N, n, R, and r, which are not defined, leading to confusion. By setting T=0, the relationship M+(m*/3)=0 is derived, resulting in m*=3 times the x-intercept. The formula's origin is clarified through the concept of the effective mass of the spring, which incorporates its kinetic energy. Understanding this relationship is crucial for accurately calculating the spring's mass in the experimental setup.
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As the title suggests, there is a practical in which we have to find mass of the spring (m*) having a block of mass M attached to bottom, from GRAPH of time period (T)^2 against M.
Here's what the practical handbook says:
T^2= [16{(pi)^2}(R^3)N][M+(m*/3)] / [(r^4)n]
there is no reference to what is N,n,R,r
What they do next is to plug in T=0
therefore, M+(m*/3)=0
=> m*/3=-M
Considering magnitude, m*=3(x intercept)

The last part makes some sense but, where does the formula come from?

Thank you! (Sorry for being messy)
 
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