Finding mass of spring from time period.

AI Thread Summary
The discussion focuses on determining the mass of a spring using the time period squared (T^2) graph against the attached block mass (M). The practical handbook provides a formula that includes variables N, n, R, and r, which are not defined, leading to confusion. By setting T=0, the relationship M+(m*/3)=0 is derived, resulting in m*=3 times the x-intercept. The formula's origin is clarified through the concept of the effective mass of the spring, which incorporates its kinetic energy. Understanding this relationship is crucial for accurately calculating the spring's mass in the experimental setup.
amk_dbz
Messages
41
Reaction score
0
As the title suggests, there is a practical in which we have to find mass of the spring (m*) having a block of mass M attached to bottom, from GRAPH of time period (T)^2 against M.
Here's what the practical handbook says:
T^2= [16{(pi)^2}(R^3)N][M+(m*/3)] / [(r^4)n]
there is no reference to what is N,n,R,r
What they do next is to plug in T=0
therefore, M+(m*/3)=0
=> m*/3=-M
Considering magnitude, m*=3(x intercept)

The last part makes some sense but, where does the formula come from?

Thank you! (Sorry for being messy)
 
Physics news on Phys.org

Thread 'Is calling fictitious forces "not real" just about terminology?'

Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
View full post »

Thread 'Derivation of Hamilton's Principle: Questions'

I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
View full post »

Similar threads

Time period of combination of massive springs in parallel
Replies
2
Views
2K
Period of a mass spring system with 2 spring of same K(vert)
Replies
1
Views
1K
I Solving for the Motion of a Spring Pendulum
2
Replies
76
Views
6K
I Mass of Backpack in Moving Elevator
Replies
10
Views
2K
Visualizing the SHM of 2 blocks attached by a spring
Replies
2
Views
2K
What is the Effect of Distributed Mass on the Time Period of a Spring?
Replies
1
Views
5K
I Units of a vector in a velocity vs time graph?
Replies
13
Views
2K
I Return to the center of the Earth
Replies
10
Views
1K
Time period of a heavy spring with an attached mass at the end
Replies
5
Views
3K
I Work-Energy Theorem for Moving Block and Spring System?
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top