Finding max height for a rocket with upwards acceleration

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Homework Help Overview

The problem involves a toy rocket launched vertically with an initial upward acceleration, followed by a phase of free fall after the motor stops. The goal is to determine the maximum height achieved by the rocket, taking into account gravitational acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to find the height, with initial attempts focusing on the upward acceleration phase. Questions arise regarding the transition to free fall and the need to account for gravitational effects after the motor stops.

Discussion Status

Participants are actively exploring different segments of the rocket's motion, with some providing calculations for both the ascent and descent phases. There is recognition of the need to convert units to kilometers, and some uncertainty remains about the calculations and assumptions made in the second phase of motion.

Contextual Notes

There is a mention of the problem's requirement to provide the answer in kilometers, which may influence the final calculations. Participants also express uncertainty about the correctness of their approaches and the values used in their equations.

garcia1
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Homework Statement


A toy rocket, launched from the ground, rises
vertically with an acceleration of 23 m/s2 for
11 s until its motor stops.
Disregarding any air resistance, what max-
imum height above the ground will the rocket
achieve? The acceleration of gravity is
9.8 m/s2 .
Answer in units of km.


Homework Equations



I used kinematics equation: x=Vo*t + 1/2at^2



The Attempt at a Solution



I was a little unsure how to go about this problem, since most free fall problems I've dealt with use only gravity as acceleration.

I tried plugging the following values into my equation:
Vo = 0m/s
a = 23 m/s^2
t = 11s

I got the answer 1391.5m, but this was wrong. I think the problem is simpler than I'm thinking about it, but I can really use some help on this.
 
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hi garcia1! :smile:

(try using the X2 and X2 icons just above the Reply box :wink:)
garcia1 said:
I tried plugging the following values into my equation:
Vo = 0m/s
a = 23 m/s^2
t = 11s

I got the answer 1391.5m …

that's the height at the end of the first stage …

you still need the extra height that it goes with a = -9.81 m/s2 :wink:
 
So what I did next is solve for the final velocity of part 1 by using the fact that Vo = 0m/s since the rocket starts from rest. Using the equation V = Vo + at, I got the equation

V = 23*11 = 253m/s

With this I placed this final velocity as the initial velocity for the next segment. I determined in this 2nd segment that X = ?, Vo = 253m/s, a = -9.81m/s^2, and Vf = 0, since the rocket must come to rest at the final height before falling.

I got the following equation:
Vf^2 = Vo^2 + 2ax -> x = Vf^2 - Vo^2 / 2a.

This answer was 3265.76m. Adding this to the initial 1391.5m, I got 4657.27m. This was wrong though, so I think there is something in this second step I'm getting wrong. Any thoughts?
 
Did you answer in terms of km, or in terms of m? :smile:
 

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