Finding Maximum and Minimum Values of T for a Rotating Block in an Inverted Cone

AI Thread Summary
The discussion focuses on determining the maximum and minimum values of the period T for a block inside a rotating inverted cone. The block must remain at a constant height H, with the cone's walls making an angle β with the vertical and a static friction coefficient μ_s. The user initially derived formulas for T_max and T_min but found discrepancies with the textbook answers, suggesting potential errors in their force diagram. Key issues identified include the placement of angle β in the force diagram and the relationship between the normal and friction forces. The conversation emphasizes the importance of accurately representing forces to solve the problem correctly.
ExpoDecay
Messages
6
Reaction score
0

Homework Statement



A small block with mass m is placed inside an inverted cone that is rotating about a vertical axis such that the time for one revolution of the cone is T. The walls of the cone make an angle β with the vertical. The coefficient of static friction between the block and the cone is \mu_{s}. If the block is to remain at a constant height H above the apex of the cone, what are the maximum and minimum values of T?

Homework Equations



\SigmaF=ma

a_{rad}=\frac{V^{2}}{R}

V=\frac{2\pi R}{T}

f_{s}=\mu_{s}n

R=H tan\beta (From diagram)

The Attempt at a Solution



As far as I can tell, the only problem I'm having is with my diagram. I first placed the x-axis along the side of the cone with the friction force parallel to it, and then moved it clockwise until the weight was parallel to the y-axis. The angles that form can be seen in the attached file, along with my work.

What I come up with is T_{max}=2\pi\sqrt{\frac{h tanβ(cosβ-\mu_{s}sinβ)}{g(sinβ+\mu_{s}cosβ)}} and T_{min}=2\pi\sqrt{\frac{h tan(cosβ+\mu_{s}sinβ)}{g(sinβ-\mu_{s}cosβ)}}

The answer that the book gives is T_{max}=2\pi\sqrt{\frac{h tanβ(sinβ+\mu_{s}cosβ)}{g(cosβ-\mu_{s}cosβ)}} and T_{min}=2\pi\sqrt{\frac{h tanβ(sinβ-\mu_{s}cosβ)}{g(cosβ+\mu_{s}sinβ)}}

I can only come up with this solution if I switch the angles around that the normal and friction forces make.

Also, the question comes from Young and Freedman 11th edition. Chapter 5, problem 5.119
 

Attachments

  • SCAN0106.jpg
    SCAN0106.jpg
    42.2 KB · Views: 2,960
Last edited:
Physics news on Phys.org
In the first force diagram β is in the wrong place?
 
Oh man, you're right! Thank you.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top